How does the target angle between the point of a dart and the bullseye in competitive darts compare to the target angle between the point of an arrow and the bullseye of a target in Olympic archery?

In darts, the throwing distance is 2.37 metres and the radius of the bullseye is 6.35mm or 0.00635 metres.
The tangent (opposite/adjacent( of half the angle between the point of the dart and the bullseye is 0.00635/2.37.
The angle is therefore 2x arctan (0.00635/2.37) = 0.307 degrees.
In Olympic archery, the distance is 70 metres and the radius of the bullseye (the inner gold circle) is 0.122 metres.
The tangent (opposite/adjacent( of half the angle between the point of the arrow and the bullseye is 0.122/70.
The angle is therefore 2x arctan (0.122/70) = 0.200 degrees.
https://www.dimensions.com/element/dartboard
https://en.wikipedia.org/wiki/Darts

This means that someone aiming at the bullseye in darts is aiming within a 50% larger angle than an Olympic archer aiming at the bullseye.