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Interesting Numbers Trivia Quiz

...well, I think they're interesting, at least. Can you identify these numbers from a unique fact about them?

A multiple-choice quiz by AdamM7. Estimated time: 4 mins.

Author
AdamM7

Time
4 mins

Type
Multiple Choice

Quiz #
365,624

Updated
Dec 03 21

# Qns
10

Difficulty
Average

Avg Score
7 / 10

Plays
678

Last 3 plays: knethen222 (10/10), arnie29387 (10/10), teachdpo (6/10).

One at a Time - Single Page - Timed Game

Question 1 of 10

1. I am the first positive number (aside from one) that is both a square and a cube number. What am I? Hint

729

128

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Question 2 of 10

2. I am the only number that is both the sum and product of three consecutive numbers - these numbers are also my only factors, meaning I am a perfect number. What am I? Hint

NEXT>

Question 3 of 10

3. I am the 21st prime. Reverse my digits and you get the 12th prime. In binary, I am a palindrome: 1001001. What am I? Hint

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Question 4 of 10

4. I am a taxicab number - I am the sum of two different pairs of cube numbers. My first two and last two digits are both prime. What am I? Hint

1729

2083

2946

2150

NEXT>

Question 5 of 10

5. I have seven unique digits. Keep doubling two and you'll reach me eventually. I am used in a digital information measuring system. What am I? Hint

2,097,152

1,048,576

9,862,451

8,462,570

NEXT>

Question 6 of 10

6. Raise my first digit to the power of one; raise my second digit to the power of two and my third digit to the power of three. These numbers add up to myself. What am I? Hint

846

149

175

671

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Question 7 of 10

7. I am the smallest positive number whose name (in British English) contains each vowel, exactly once. What am I? Hint

148

1084

206

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Question 8 of 10

8. In Roman numerals, I am CXLI. My digits are the first three decimal places of pi (not rounding). What am I? Hint

279

186

141

245

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Question 9 of 10

9. I am the lowest number whose digits, when added up together, can be cubed to equal myself. I am also the number of bytes in half a kilobyte and a power of two. What am I? Hint

343

416

729

512

10. I am a Fibonacci prime. I am the hypotenuse of a Pythagorean triple (a right-angled triangle with side lengths that are all whole numbers). I am equal to a baker's dozen, and the fear of me is called triskaidekaphobia. What am I? Hint

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Most Recent Scores

Dec 18 2024 : knethen222: 10/10
Nov 22 2024 : arnie29387: 10/10
Nov 19 2024 : teachdpo: 6/10

Score Distribution

Quiz Answer Key and Fun Facts

1. I am the first positive number (aside from one) that is both a square and a cube number. What am I?

Answer: 64

Any number that is a square and a cube number is also a sixth power (2x3) - the lowest sixth power, aside from one, is 2x2x2x2x2x2 = 64.

To check, the square root of 64 is eight (or -8) and the cube root of 64 is four.

2. I am the only number that is both the sum and product of three consecutive numbers - these numbers are also my only factors, meaning I am a perfect number. What am I?

Answer: 6

A perfect number is one whose factors (other than itself) add up to make that number. Six is the first perfect number, because its factors are one, two and three (six isn't included).

One, two and three added together make six, and multiplied together make six.

3. I am the 21st prime. Reverse my digits and you get the 12th prime. In binary, I am a palindrome: 1001001. What am I?

Answer: 73

73 is the 21st prime number - 21 is also the number you get when multiplying its digits (seven and three) together. Its mirror, 37, is the 12th prime number (12 being the mirror of 21). In binary, 1001001 (64+8+1) is 73, and it is a palindromic number, since it reads the same backwards and forwards.

4. I am a taxicab number - I am the sum of two different pairs of cube numbers. My first two and last two digits are both prime. What am I?

Answer: 1729

Both 17 and 29 are prime numbers. 1729 is the sum of 1^3 (one) and 12^3 (1728). It is also the sum of 9^3 (729) and 10^3 (1000). 1729 = 1+1728 = 729+1000

5. I have seven unique digits. Keep doubling two and you'll reach me eventually. I am used in a digital information measuring system. What am I?

Answer: 1,048,576

2,097,152 (although 2^21) has a repeated digit (two). 9,862,451 is odd, so can't possibly be two to the power of anything. 8,462,570 ends in a 0, and even if you keep doubling two forever, you will never reach a number ending in 0, because when doubling, the last digit follows a pattern - 2, 4, 8, 6, 2...

1,048,576 is a power of two: 2^20. It has seven unique digits (0, 1, 4, 5, 6, 7, 8) and a (binary) megabyte (a measure of digital information) is 1,048,576 bytes.

6. Raise my first digit to the power of one; raise my second digit to the power of two and my third digit to the power of three. These numbers add up to myself. What am I?

Answer: 175

1^1 = 1
7^2 = 49
5^3 = 125.
125+49+1 = 175.

There are also other numbers with this property: 135, 518 and 598, for instance.

7. I am the smallest positive number whose name (in British English) contains each vowel, exactly once. What am I?

Answer: 206

twO-hUndrEd And sIx contains each of the five vowels once.

one-thousand And EIghty-fOUr contains all five vowels in alphabetical order, although some vowels are repeats.

8. In Roman numerals, I am CXLI. My digits are the first three decimal places of pi (not rounding). What am I?

Answer: 141

Pi, to four decimal places, is 3.1415.

In Roman numerals, "C" represents 100, "XL" represents ten (X) less than 50 (L) and I represents one. 100+(50-10)+1 = 141.

9. I am the lowest number whose digits, when added up together, can be cubed to equal myself. I am also the number of bytes in half a kilobyte and a power of two. What am I?

Answer: 512

5+1+2 = 8.
8^3 = 512.

There are 1024 bytes in a (binary) kilobyte, so 512 in half a kilobyte. Since 512 is a power of two (2^9), it is often the maximum amount of information that can be stored on several binary systems - it is a common disk sector size, for instance.

Answer: 13

A Fibonacci prime is simply a prime number (2, 3, 5, 7, 11, 13 etc.) that is also a member of the Fibonacci sequence (1, 2, 3, 5, 8, 13 etc.)

5, 12 and 13 form a Pythagorean triple, because 5^2 (25) and 12^2 (144) add up to 13^2 (169).

A baker's dozen is one larger than a normal dozen - 13, and triskaidekaphobia is the fear of the number 13, stemming from "tri-" (3), "deka" (10) and "-phobia" (irrational fear).

Source: Author AdamM7

This quiz was reviewed by FunTrivia editor WesleyCrusher before going online.
Any errors found in FunTrivia content are routinely corrected through our feedback system.

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This quiz is part of series All About Numbers:

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Referenced Topics

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