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Quiz about I Am Special Too
Quiz about I Am Special Too

I Am Special, Too! Trivia Quiz


Can you identify the ten numbers based on the descriptions and clues given? Enjoy!

A multiple-choice quiz by Matthew_07. Estimated time: 7 mins.
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Author
Matthew_07
Time
7 mins
Type
Multiple Choice
Quiz #
310,176
Updated
Dec 03 21
# Qns
10
Difficulty
Tough
Avg Score
6 / 10
Plays
1197
Awards
Top 35% Quiz
- -
Question 1 of 10
1. I am the smallest positive integer that can be divided completely by 2, 4, 6, 8 and 10. What number am I?

Answer: (3-digit number)
Question 2 of 10
2. I am the sum of the smallest two-digit prime number and the greatest two-digit square number. What number am I?

Answer: (2-digit number)
Question 3 of 10
3. The smallest three-digit palindromic square number is 121. I am the second smallest number with such properties. My first digit is 4 and the sum of all my three digits is 16. What number am I?

Answer: (3-digit number)
Question 4 of 10
4. The sum of my two digits is the same as the product of my two digits. I am a multiple of 11. What number am I?

Answer: (2-digit number)
Question 5 of 10
5. The numbers 4 and 6 are the first two numbers that are the averages (or the means) of two consecutive prime numbers that differ by 2. I am the third number that has the same properties. What number am I?

Answer: (2-digit number)
Question 6 of 10
6. I am the smallest square number that is the sum of two different positive cube numbers. What number am I?

Answer: (1-digit number)
Question 7 of 10
7. I am the remainder of a! / b!, where a and b are any positive integers with a > b. Here, a! means a factorial. What number am I?

Answer: (1-digit number)
Question 8 of 10
8. The smallest number that is neither prime nor even is 1. I am the second number with these properties. What number am I?

Answer: (1-digit number)
Question 9 of 10
9. The first four Fibonacci numbers that are also prime are 2, 3, 5 and 13. I am the next prime Fibonacci number. What number am I?

Answer: (2-digit number)
Question 10 of 10
10. I am the smallest positive integer that has the following properties. When I am divided by 2, the remainder is 1. When I am divided by 3, the remainder is 2. When I am divided by 4, the remainder is 3. What number am I?

Answer: (2-digit number)

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Quiz Answer Key and Fun Facts
1. I am the smallest positive integer that can be divided completely by 2, 4, 6, 8 and 10. What number am I?

Answer: 120

To solve this problem, we need to find the smallest common multiples for these 5 numbers, namely 2, 4, 6, 8 and 10. Notice that 120/2 = 60, 120/4 = 30, 120/6 = 20, 120/8 = 15, 120/10 = 12.
2. I am the sum of the smallest two-digit prime number and the greatest two-digit square number. What number am I?

Answer: 92

The smallest two-digit prime number is 11. On the other hand, we note that 10^2 = 100 is a three-digit square number. So, the greatest two-digit square number is 9^2 = 81. The sum of these two numbers is 11 + 81 = 92.
3. The smallest three-digit palindromic square number is 121. I am the second smallest number with such properties. My first digit is 4 and the sum of all my three digits is 16. What number am I?

Answer: 484

Square numbers that are greater than 100 are 121, 144, 169, ... The list goes on. In order to find the next three-digit palindromic square number, we are told that the sum of all the three digits is 16 and the first digit is 4. This implies that the last digit of the number is also 4. 16 - 4 - 4 = 8. So the number is 484.
4. The sum of my two digits is the same as the product of my two digits. I am a multiple of 11. What number am I?

Answer: 22

Let the number be 10a + b. So, a + b = ab. By inspection, we find out that when a = b = 2, a + b = ab = 4. So, the number = 10a + b = 22.
5. The numbers 4 and 6 are the first two numbers that are the averages (or the means) of two consecutive prime numbers that differ by 2. I am the third number that has the same properties. What number am I?

Answer: 12

The first few prime numbers are 2, 3, 5, 7, 11, 13... Notice that (11 + 13)/2 = 12.
6. I am the smallest square number that is the sum of two different positive cube numbers. What number am I?

Answer: 9

First, we list down the first few cube numbers, namely 1, 8, 27, 64, 125... Observe that 1 + 8 = 9 = 3^2. So the answer is 9.
7. I am the remainder of a! / b!, where a and b are any positive integers with a > b. Here, a! means a factorial. What number am I?

Answer: 0

Let's take a specific example. Let a = 4 and b = 3. So, a! / b! = 4! / 3! = 4. The remainder is 0. In fact, given any value of a and b, with the condition a > b, the remainder of the division operation a! / b! is zero.
8. The smallest number that is neither prime nor even is 1. I am the second number with these properties. What number am I?

Answer: 9

Let's list down the first few positive integers and then we examine it one by one. 1, 2, 3, 4, 5,6 7, 8, 9, 10. Since one of the requirement is that the number is not an even number, it leaves us with only 1, 3, 5, 7, 9. 1 is not a prime number. 3, 5 and 7 are all prime numbers. 9 is not a prime number because 9 = 3 x 3. So, 9 is the second smallest number that is neither prime nor even.
9. The first four Fibonacci numbers that are also prime are 2, 3, 5 and 13. I am the next prime Fibonacci number. What number am I?

Answer: 89

The first few Fibonacci numbers are 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89...

Checking the list, we find out that 89 is the fifth prime Fibonacci number.
10. I am the smallest positive integer that has the following properties. When I am divided by 2, the remainder is 1. When I am divided by 3, the remainder is 2. When I am divided by 4, the remainder is 3. What number am I?

Answer: 11

Let's denote the number as x.

x/2 = b + 1/2 ==> x = 2b + 1
x/3 = c + 2/3 ==> x = 3c + 2
x/4 = d + 3/4 ==> x = 4d + 3

We are not interested in finding the values of b, c and d. We only need to find the value of x.
Let the number be x. Notice that 2b + 1 = x is an odd number. Also, x = 2b + 1 = 3c + 2. So, 3c + 2 is an odd number. This implies c is an odd number as well.

3c + 2 = 4d + 3
3c = 4d + 1
When d = 2, c = 3. Also, b = 5. So, the answer is 2(5) + 1 = 11.
Source: Author Matthew_07

This quiz was reviewed by FunTrivia editor crisw before going online.
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Related Quizzes
This quiz is part of series Guess the Numbers:

Guess the numbers (positive integers) based on the clues and descriptions given.

  1. I Am Special! Tough
  2. I Am Special, Too! Tough
  3. Numbers Costume Party! Average
  4. Palindromic Numbers Party! Average
  5. Mathematicians and Discoveries! Average
  6. Dealing with Dark Digits Average
  7. Sorry, Wrong Number Easier

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