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Fun Mathematical Problems II Trivia Quiz

Part two of a series of quizzes on maths and easy statistics. Have fun.

A multiple-choice quiz by wimm. Estimated time: 5 mins.

Author
wimm

Time
5 mins

Type
Multiple Choice

Quiz #
48,703

Updated
Dec 03 21

# Qns
5

Difficulty
Tough

Avg Score
3 / 5

Plays
3592

One at a Time - Single Page - Timed Game

Question 1 of 5

1. While you're reading this, I take my favourite CD which I have twice (okay, I'm a big fan and wanted to support this group). If you know there are 10 numbers on the CD and I put them both in separate CDplayers that both have 'the random play' button on it. When I put them both on random play, how big is the probability I will hear the same song at the same time?

Answer: (number : number)

NEXT>

Question 2 of 5

2. Same question, but how big is the probability that I will hear the song 'Marian' at the same time(keep in mind there are 10 numbers on the CD)?

Answer: (number : number)

NEXT>

Question 3 of 5

3. When I take the digits 1, 2, 3, 4, and 5, how many different 5 digit numbers can be formed if you may not use the same digit twice in the number? Hint

100

125

120

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Question 4 of 5

4. Slightly different: When I take the digits 1, 2, 3, 4, and 5, how many different 5 digit numbers can be formed if every digit can be used as often as desired? Hint

3225

3125

2500

4250

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Question 5 of 5

5. Without using a calculator, can you give me the factors of the number 119 (and no, it's not 1 and 119)?

Answer: (two numbers, a comma to separate them)

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Quiz Answer Key and Fun Facts

Answer: 1:10

The first CD can play any number (odds 10:10), the other has to pick the same number (prob. 1:10). The total probability is thus 1:10.

2. Same question, but how big is the probability that I will hear the song 'Marian' at the same time(keep in mind there are 10 numbers on the CD)?

Answer: 1:100

The probability the first CD player takes 'Marian' is 1:10. The same for the second CD player. Since these events are not dependent, the total probability needs to be multiplied, thus the result becomes 1:100.

3. When I take the digits 1, 2, 3, 4, and 5, how many different 5 digit numbers can be formed if you may not use the same digit twice in the number?

Answer: 120

The first digit can be any digit of the 5, for the second digit only 4 digits are possible, for the third only 3, ... This is the factorial(!) of 5 we are looking for. 5x4x3x2x1=120.

4. Slightly different: When I take the digits 1, 2, 3, 4, and 5, how many different 5 digit numbers can be formed if every digit can be used as often as desired?

Answer: 3125

For the first digit we have five possibilities, for the second also, for the third... So the total amount of different numbers equals 5x5x5x5x5=3125.

5. Without using a calculator, can you give me the factors of the number 119 (and no, it's not 1 and 119)?

Answer: 17, 7

119 = 144 - 25. The general formula is (a x a - b x b) = (a - b)x(a + b). Thus, the result is 12 - 5 and 12 + 5...

Source: Author wimm

This quiz was reviewed by FunTrivia editor crisw before going online.
Any errors found in FunTrivia content are routinely corrected through our feedback system.

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Referenced Topics

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