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Quiz about Pencils Down in 3 2 1
Quiz about Pencils Down in 3 2 1

Pencils Down in 3, 2, 1... Trivia Quiz


Have you ever run out of time in math class and needed to make a few guesses at the end to try and salvage your grade? Here are a few helpful hints for a multiple choice quiz on multiplication that may save you time if you are run up against a deadline.

A multiple-choice quiz by kstyle53. Estimated time: 5 mins.
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Author
kstyle53
Time
5 mins
Type
Multiple Choice
Quiz #
354,338
Updated
Dec 03 21
# Qns
10
Difficulty
Average
Avg Score
8 / 10
Plays
1300
Awards
Top 35% Quiz
Last 3 plays: Guest 104 (10/10), Linda_Arizona (9/10), Guest 76 (10/10).
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Question 1 of 10
1. The first problem does not seem all that hard - all your teacher wants you to do is multiply a number by 2. Unfortunately it's a pretty big number and you do not want to waste too much time solving it. You look at the four multiple choice options, and are relieved when you look at the last digit of each of the numbers. Which of the following options is the only possible answer to this question? Hint


Question 2 of 10
2. Your teacher knows you are pretty smart, so she decides to up the ante and asks you which of the numbers given can be divided by 3. Fortunately, you remember a little trick about the digits of any number divisible by 3. Which of the following is ALWAYS a true statement and can be used to help find the right answer? Hint


Question 3 of 10
3. Your teacher has decided to throw you a curve ball! She asks you which of the following numbers is not divisible by 5. At first you are scared that you have to perform division for four different numbers. However, you look over the list and breathe a sigh of relief. Which of the following numbers is NOT divisible by 5? Hint


Question 4 of 10
4. Perhaps your teacher senses that the last question was a little unfair, so she decides to revert back to asking you to perform multiplication for just one number. This time, she asks you to multiply a number by 10. How can you accomplish this feat quickly? Hint


Question 5 of 10
5. Sometimes you can combine rules to help you with other numbers. That will come in handy, because your teacher has asked you to find a multiple of 6. You realize that 6 is a multiple of two other numbers and you already have shortcuts for them. what are those two numbers, which can be used to help you find the multiple of 6? Hint


Question 6 of 10
6. You are halfway there! These hints are saving you time, but you know it's going to be close. Perhaps realizing that you might run of out of time, your teacher decides to ask you a question that may be helpful later on if you need to randomly guess an answer. Your teacher asks you to look at the following options. Which one will give an odd number for an answer? Hint


Question 7 of 10
7. You look at the quiz and are befuddled. The problem calls for you to multiply the number 16 and 19. You know you are running short on time and you figure your best best bet is to estimate the answer by substituting easy number to multiply. Which of the following will yield the closest estimate to the real value? Hint


Question 8 of 10
8. You can see the end of the quiz, but you don't have time to relax quite yet. The teacher seems primed to stump you and gives you four different numbers. She then asks you to identify which number is prime (has no factors other than 1 and itself). Can you use some multiplication shortcuts to identify the prime number from the choices below? Hint


Question 9 of 10
9. To keep things even, your teacher decides to flip the question around. This time, she gives you a list of four numbers and asks you to find the composite one (has factors other than 1 and itself). Can you find the composite number by using what you know about multiplication? Hint


Question 10 of 10
10. You've made it to end. Are you feeling excited? Your teacher must be, because the final question asks you to find the value of "6!". While 6 can be a pretty exciting number, your teacher probably didn't put that "!" at the end by accident. It's more likely she is using the notation for a factorial and wants to know what the value of 6 x 5 x 4 x 3 x 2 x 1 is. Can you help her out? Hint





Most Recent Scores
Nov 18 2024 : Guest 104: 10/10
Nov 18 2024 : Linda_Arizona: 9/10
Nov 16 2024 : Guest 76: 10/10
Nov 02 2024 : bradncarol: 7/10
Oct 23 2024 : MikeMaster99: 9/10
Oct 20 2024 : Guest 174: 8/10
Oct 10 2024 : Guest 130: 9/10

Score Distribution

quiz
Quiz Answer Key and Fun Facts
1. The first problem does not seem all that hard - all your teacher wants you to do is multiply a number by 2. Unfortunately it's a pretty big number and you do not want to waste too much time solving it. You look at the four multiple choice options, and are relieved when you look at the last digit of each of the numbers. Which of the following options is the only possible answer to this question?

Answer: 738,516,294

Since you are multiplying the number by 2, the answer must be divisible by 2. For this to happen, the digit in the 'ones' place (the "last" digit of the number) must be even (0, 2, 4, 6, or 8). Therefore we can eliminate the potential answers that end in 1, 7, and 9. By the process of elimination, we are left with the only choice that ends in an even number.
2. Your teacher knows you are pretty smart, so she decides to up the ante and asks you which of the numbers given can be divided by 3. Fortunately, you remember a little trick about the digits of any number divisible by 3. Which of the following is ALWAYS a true statement and can be used to help find the right answer?

Answer: For any number that is divisible by 3, the sum of the individual digits of that number must be divisible by 3

While it's possible the sum of the digits could equal 3, or be greater than 3, this is the only statement that is ALWAYS true. The sum of the digits can never be less than 3, so that statement is always false.
As an example, you can look at the number 99. If you add the digits together, you get 9 + 9 = 18. You may recognize that 18 is divisible by 3, but you could add up those digits as well to get 1 + 8 = 9. Hopefully at this point you know 9 is divisible by 3, and therefore you know that 99 is also divisible by 3.
3. Your teacher has decided to throw you a curve ball! She asks you which of the following numbers is not divisible by 5. At first you are scared that you have to perform division for four different numbers. However, you look over the list and breathe a sigh of relief. Which of the following numbers is NOT divisible by 5?

Answer: 123,456,789

It's actually pretty easy to figure out if a number is divisible by 5. Like the number 2, you only need to look at the digit in the 'ones' place at the end of the number. However, for a number to be divisible by 5, the 'ones' place has only two options, 0 or 5. Since three of these numbers end in 0 or 5, they can be eliminated as choices, leaving the correct answer of 123,456,789.
4. Perhaps your teacher senses that the last question was a little unfair, so she decides to revert back to asking you to perform multiplication for just one number. This time, she asks you to multiply a number by 10. How can you accomplish this feat quickly?

Answer: Write the number down and add a "0" to the end of it

Any number that is divisible by 10 will end in a 0. Instead of performing the multiplication, just go ahead and add a "0" to the given number. For example, if the problem is 7 x 10, you can add a "0" to 7 and get an answer of 70. On a larger scale, this principle works for any multiple of 10, such as 100, 1,000, 1,000,000, etc. All you have to do is count the "0's" at the end of the multiple of 10 and add them to the end of the original number.
5. Sometimes you can combine rules to help you with other numbers. That will come in handy, because your teacher has asked you to find a multiple of 6. You realize that 6 is a multiple of two other numbers and you already have shortcuts for them. what are those two numbers, which can be used to help you find the multiple of 6?

Answer: 2 and 3

Since 2 and 3 are prime factors of 6, you can figure out if a number is divisible by 6 if it is divisible by both 2 and 3. It is not enough for the number to meet the conditions of only 2 or only 3. For example, 8 is divisible by 2, but it is not divisible by 3 or 6. Likewise, 9 is divisible by 3, but it is not divisible by 2 or 6. Since 12 is divisible by both 2 and 3, it is also divisible by 6.
6. You are halfway there! These hints are saving you time, but you know it's going to be close. Perhaps realizing that you might run of out of time, your teacher decides to ask you a question that may be helpful later on if you need to randomly guess an answer. Your teacher asks you to look at the following options. Which one will give an odd number for an answer?

Answer: Multiplying an odd number by an odd number

The only way to get an odd number via multiplication is to multiply two odd numbers. If any of the numbers are even, the final product will also be even. This is consistent with the rules of multiplying by 2, since multiplying a number by 2 will always give an even answer.

This will hold true regardless of how many odd numbers are multiplied with an even number. Knowing this may allow you to eliminate impossible choices in the quiz, increasing the chance you will guess correctly if you are forced to randomly pick an option.
7. You look at the quiz and are befuddled. The problem calls for you to multiply the number 16 and 19. You know you are running short on time and you figure your best best bet is to estimate the answer by substituting easy number to multiply. Which of the following will yield the closest estimate to the real value?

Answer: 15 x 20 = 300

The correct answer is 304, so an estimate of 300 is the closest option. When estimating, it's a good rule to keep the numbers as close to the real numbers as possible to ensure a reasonable approximation. By making the numbers easier to multiply together, you can save a lot of time and hopefully eliminate some bad answers.

At that point, you can guess an answer that is close to your estimate, and then come back and work out the correct answer if you finish the quiz early.
8. You can see the end of the quiz, but you don't have time to relax quite yet. The teacher seems primed to stump you and gives you four different numbers. She then asks you to identify which number is prime (has no factors other than 1 and itself). Can you use some multiplication shortcuts to identify the prime number from the choices below?

Answer: 101

Using the process of elimination, you can arrive at the answer of 101. Since the number 115 ends in a 5, we know it's divisible by 5 and therefore not prime. Since 92 ends in a 2, we know it's divisible by 2. The number 117 may be tricky to handle at first, but it's actually divisible by 3. If we add the digits together, we get 1 + 1 + 7 = 9, which is divisible by 3. Since we can use the multiplication short cuts to eliminate three of the choices, 101 must be prime.
9. To keep things even, your teacher decides to flip the question around. This time, she gives you a list of four numbers and asks you to find the composite one (has factors other than 1 and itself). Can you find the composite number by using what you know about multiplication?

Answer: 147

This one could be pretty difficult if you don't spot the trick. Hopefully though, you decided to check if any of the numbers are divisible by 3. If you did, you realized that 1 + 4 + 7 = 12. Knowing that 12 is divisible by 3, you can then determine that 147 is composite. Unlike other number like 2 or 5, you cannot just look at the digit in the one's place to determine if a number is divisible by 3.

However, it's a good idea to always check for divisibility by 3 just in case it saves you a lot of work checking other numbers.
10. You've made it to end. Are you feeling excited? Your teacher must be, because the final question asks you to find the value of "6!". While 6 can be a pretty exciting number, your teacher probably didn't put that "!" at the end by accident. It's more likely she is using the notation for a factorial and wants to know what the value of 6 x 5 x 4 x 3 x 2 x 1 is. Can you help her out?

Answer: 720

We are looking for a number that is divisible by 2, 3, 4, 5, and 6. If we can eliminate choices, we can easily find the correct answer. The number 715 is not divisible by 2, since it does not end in a 0, 2, 4, 6, or 8. 721 is not divisible by 5, since it does not end in a 0 or 5. From here, we can check the final two numbers to see if they are divisible by 3.

The sum of the digits of 730 = 7 + 3 + 0 = 10, which is not divisible by 3. The sum of the digits of 720 = 7 + 2 + 0 = 9, which is divisible by 3, so 720 is the correct answer.
Source: Author kstyle53

This quiz was reviewed by FunTrivia editor NatalieW before going online.
Any errors found in FunTrivia content are routinely corrected through our feedback system.
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